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Gvd
a fost răspuns

afla toate nr nat care ,împartite la 9,dau catul 25 si retul mai mare decat 5

Răspuns :

TomaMath
n : 9 = 25 r >5 
=> r E { 6,7,8,9,10...,24}
=> n = 9 * 25 + r
     n = 225 +r
Deci nr sunt 231,232,233,234,235,236,237,238,239,240,241,242,243,244,245,246,247,248,249

Succes!
Bebedumi70
x=25*9+6
x=225+6
x=231
231:9=25 r 6

x=25*9+7
x=225+7
x=232
232:9=25 r 7

x=25*9+8
x=225+8
x=233
233:9=25 r 8

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