Răspuns :
(2x-1)^2=(2x)^2-4*x+1 = 4(x)^2-4*x+1
4(x)^2-4*x+1 = 0
D= (b)^2-4*a*c
D=16-4*4 = 0
x1=x2 = -b/2*a = 4/2 = 2
4(x)^2-4*x+1 = 0
D= (b)^2-4*a*c
D=16-4*4 = 0
x1=x2 = -b/2*a = 4/2 = 2