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a fost răspuns

daca a+b=17 si b+c= 15, calculati a+3b+2c; 4a+7b+3c

Răspuns :

Frunza65
a+3b+2c=a+b+2b+2c=a+b+2(b+c)=17+2x15=17+30=47
4a+7b+3c=4a+4b+3b+3c=4(a+b)+3(b+c)=4x17+3x15=68+45=113
Zitafiles
a+3b+2c=a+b+2b+2c=a+b+2(b=c)=17+2*15=47
4a+7b+3c=4a+4b+3b+3c=4*(a+b)+3*(b+c)=4*17+3*15=68+45=113

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