4) a=3x15+2
a=47
b=7x9+5
b=63+5
b=68
c=60÷12
c=5
d=95÷5
d=19
5) 112÷7=16
49÷7+63÷7
7+9=36
27÷3=9
63÷3-36÷3
21-12=9
8-6=2
(96-72)÷12
24÷12=2
7-5=2
(98-70)÷14
28÷14=2
6) prima fata= 12x8+10=96+10=106
a doua fata=4×15+3=60+3=63
a treia fata=12×2+9=24+9=33
A doua fetita a rezolvat corect impartirea.
Sper ca te-am ajutat!!
