a) M(NaCl) = 23+35,5= 58,5 g/mol
b)M(NaHCO3) = 23+1+12+(3×16)= 36+48= 84
g/mol
c)M(CH3COOH)=12+3×1+12+16+16+1=70 g/mol
d)M(C2H2OH)=2×12+2×1+16+1=43 g/mol
e)M(C6H12O6)=(6×12)+(12×1)+(6×16)=180 g/mol
f)M(C12H22O11)=(12×12)+(22×1)+(11×16)=342
g/mol
h)M(CaCO3)= 40+12+(3×16)=100 g/mol
i)M(Ca(OH)2)= 40+(2×16)+(2×1)=74 g/mol
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