Q= (C + mc)Δt unde Δt= n,apaxΔH
m=150g=0,150kg
c=4,18J/gr.grad=4,18kJ/gr.grad
1cal= 4,18J---> ΔH= 18,5x4,18kj/mol=77,33kJ/mol
Q= n,apax ΔH
din ecuatia 2NaOH+H2SO4---> Na2SO4 + 2H2O
n,apa= n,NaOH=n,H2SO4/2= 0,05 mol deoarece
n,NaOH=c x V=0,5X01= = 0,05mol
c,m,acid=2c,n= 2M---> n,acid= 2x0,05= 0,1mol si 0,1/2= 0,05mol
Q=77,33Kj/molx0,05mol=3,866Kj
3,866= (C+ 0,150X4,18)5..................CALCULEAZA C !
cred ca este bine !!!!!
