a)
[tex] {9}^{0} + {1}^{8} + {8}^{1} + {0}^{2004} = \\ 1 + 1 + 8 + 0 = 10[/tex]
Deoarece orice numa la puterea 0 e ega cu 1, si 0 la orice putere e 0
b)
[tex]7 \times {2}^{1997} - 6 \times {2}^{1996} - 2 \times {2}^{1998} = \\ {2}^{1996} (7 \times 2 - 6 - 2 \times {2}^{2} ) = \\ {2}^{1996} \times (14 - 14) = \\ {2}^{1996} \times 0 = 0[/tex]
