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Marasbarcea
a fost răspuns

Calculati: a) 7^40:49^20+32^7+100^30:10^58
b)(1+3+3^2+3^3):5-30:(1+2+2^2+2^3).

Răspuns :

Didi12342
7^40:49^20+32^7+100^30:10^58 =

= 7^40:(7^2)^20+32^7+(10^2)^30:10^58 =

= 7^40:7^40+32^7+10^60:10^58 =

= 1 + (2^5)^7 + 10^2 =

= 2^35 + 101

b)(1+3+3^2+3^3):5-30:(1+2+2^2+2^3) =

= (4 + 9 + 27) : 5 - 30:(3+4+8) =

= 40 : 5 - 30 : 15 =

= 8 - 2 =

= 6