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a fost răspuns

a= 2(1+3+3²+...+3²⁰)
b=(3⁷)⁵x 3¹⁰: 9¹²
comparale

Răspuns :

Crazymonkey98
a=2*(3^21-1)/2=3^21 -1
b=3^35 x 3^10:3^24=3^21
b>a
S=1+3+3^2+....+3^20 |3
3S=3+3^2+3^3+...+3^21
scazand cele două sume
2S=3^21-1
S=(3^21-1)/2
a=2×(3^21-1)/2=3^21-1
b=3^35×3^10:3^24=3^(45-24)=3^21
a<b