aplici lema lui stoltz
notezi an numaratorul si bn numitorul
lim an+1-an/(bn+1-bn)=lim an/bn
Lim (an+1-an)/(bn+1-bn)=[(√2+∛3+...+(n)√n+(n+1)√(n+1)-(√2+∛3+....+(n√n)]/[ln(n+1)-ln n]=
lim(n+1)√(n+1)/ln(n+1)/n=lim(n+1)√(n+1)/1=lim(n+1)√(n+1)
Aplici creiteriul radacinii
lim(n+1)√(n+1)=lim an+2/an+1=lim(n+2)/(n+1)=1
