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Teddy101
a fost răspuns

ma poate ajuta cineva cu acest exercitiu repede?? (2017^0+27^27:9^40)^50:32^20=

Răspuns :

Alitta
(2017^0+27^27:9^40)^50:32^20=

= (  1     +3⁸¹ : 3⁸⁰ )⁵⁰ : 32²⁰ = 

=                        4 ⁵⁰  : 32⁴⁰ = 2¹⁰⁰ : (2⁵)²⁰ =

=                       2¹⁰⁰ : 2¹⁰⁰ = 2⁰ = 1 !!!
Ahmed1985
= (1+(3^3)^27:(3^2)^40)^50:(2^5)^20
= (1+3^81:3^80)^50:2^100
= (1+3)^50:2^100
= 4^50:2^100
= (2^2)^50:2^100
= 2^100:2^100
= 2^0
= 1
Sper ca te-am ajutat !

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