👤

EX 10...DAR DE DATA ASTA SA MAI FIE SI CORECTA !AM PUS-O DE 5 ORI ACEASTA INTREBARE SI NIMENI NU A VRUT SA MA AJUTA !AJUTOR!!!!

EX 10DAR DE DATA ASTA SA MAI FIE SI CORECTA AM PUSO DE 5 ORI ACEASTA INTREBARE SI NIMENI NU A VRUT SA MA AJUTA AJUTOR class=

Răspuns :

[tex]2 \frac{3}{4}+5 \frac{1}{4}= \frac{11}{4}+ \frac{21}{4}= \frac{11+21}{4}= \frac{32}{4}=8 [/tex]
[tex]3 \frac{1}{5}+7 \frac{3}{5}=10 \frac{4}{5} [/tex]
[tex]3 \frac{1}{5}+4 \frac{1}{6}= \frac{16}{5}+ \frac{25}{6}= \frac{96}{30}+ \frac{125}{30}= \frac{96+125}{30}= \frac{221}{30}=7 \frac{11}{30} [/tex]
[tex]7 \frac{5}{6}+11 \frac{3}{4}= \frac{47}{6}+ \frac{47}{4}= \frac{94}{12}+ \frac{141}{12}= \frac{235}{12}= 19\frac{7}{12} [/tex]
a)( 5x3+1)/5+(5x7+3)/5=16/5+38/5=(16+38)/5=54/5
b) (4x2+3)/4 +(4x5+1)/4=11/4+21/4=(11+21)/4=32/4=8
c) (5x3+1)/5 +(6x4+1)6=16/5+25/6=(16x6)/30 +(25x5)/30=(96+125)/30=221/30
d) (6x7+5)/6 +(4x11+3)/4=47/6+47/4= (47x2)/12+ (47x3)/12=(94+141)12=235/12