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Aflați x din 12+[104:26+2×(3×5-×)-12÷2]÷2=15

Răspuns :

Alitta
12+[104:26+2×(3×5-×)-12÷2]÷2=15

[104:26+2×(3×5-×)-12÷2]÷2=3

104:26+2×(3×5-×)-12÷2=6

104:26+2×(3×5-×)=12

2×(3×5-×) = 12- 4 = 8

(3×5-×) = 4

x = - 11








Frunza65
12+[4+2x(15-x)-6]=15x2
12+[4+2x(15-x)-6]=30
4+2x(15-x)-6=30-4
2x(15-x)=26+6
2x(15-x)=32
15-x=32:2
15-x=16
15-16=x
 x=-1

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