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Cat face f'(x)= 1/x+lnx

Răspuns :


[tex]\it f(x) = \dfrac{1}{x} +lnx = x^{-1} +lnx \\\;\\ \\\;\\ f'(x) = (x^{-1})'+(lnx)' = -1\cdot x^{-1-1} +\dfrac{1}{x} = -x^{-2} +\dfrac{1}{x}=\dfrac{1}{x}-\dfrac{1}{x^2}=\dfrac{x-1}{x^2}[/tex]


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