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Andreea678
a fost răspuns

Calculeaza:

a) 5 la puterea 140:25 la puterea 70+8 la puterea 32:16 la puterea 24+100 la puterea 26:10 la puterea 48-2 la puterea 5*5 la puterea 2
b) [3 la puterea 100:3 la puterea 10+(9 la puterea 5*3 la puterea 14)la puterea 5:27 la puterea 10+(4 la puterea 30:4 la puterea 29-1 la puterea 70)la puterea 102:81 la puterea 3]:(2 la puterea 10:2 la puterea 9+2 la puterea 0)la puterea 90

Dau coroana

Răspuns :

NeymarPSG
a)5^140:(5^2)^70+(2^3)^32:(2^4)^24+(10^2)^26:10^48-2^5x5^2=
1+2^96:2^96+10^52:10^48-32x25
1+1+10000-800=9202
b){3^100:3^10+[(3^2)^5x3^14]^5:(3^3)^10+[(2^2)^30:(2^2)^29-1]^102:(3^4)^3}:
(2^1+1)^90=
[3^90+(3^10x3^14)^5:3^30+(2^60:2^58-1)^102:3^12]:3^90
(3^90+3^120:3^30+3^102:3^12):3^90
(3^90+3^90+3^90):3^90
3^92:3^90
3^2