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Damaris19
a fost răspuns

descompuneti in factori:
x³+6x²+12x+8=?

Răspuns :



x³ + 6x² +12x + 8 = x³ + 2x² + 4x² + 8x + 4x  + 8 = x²(x+2) +4x(x+2) +4(x+2)=

=(x+2)(x²+4x+4) =(x+2)(x+2)² = (x+2)³
x^3+6x^2+12x+8=
(x^3+2x^2)+(4x^2+8x)+(4x+8)=
x^2(x+2)+4x(x+2)+4(x+2)=
(x+2)(x^2+4x+4)=
(x+2)(x+2)^2=
(x+2)^3

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