Răspuns :
CH2=C(CH3)-CH3 + [O] + H2O⇒ HO-CH2-(HO)C(CH3)-CH3
2KMnO4 + H2O = 2KOH + 2MnO2 + 3[O]
n butena/nKMnO4 = 3/2 nKMnO4 = 2/3 moli
Vs = n/cM = 2/3 ·10/2 = 10/3 l
2KMnO4 + H2O = 2KOH + 2MnO2 + 3[O]
n butena/nKMnO4 = 3/2 nKMnO4 = 2/3 moli
Vs = n/cM = 2/3 ·10/2 = 10/3 l