Răspuns :
2 Al + Fe2O3 = Al2O3 + 2 Fe
M Al = 27 g/mol
M Fe = 56 g/mol
2*27 g Al............2*56 g Fe
x..............................11,2 g Fe
x = 5,4 g Al
M Al = 27 g/mol
M Fe = 56 g/mol
2*27 g Al............2*56 g Fe
x..............................11,2 g Fe
x = 5,4 g Al