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Cosmosamini1
a fost răspuns

Calculeaza impartind fiecare termen al sumei la impartitor :
a) (21+14+35):7=
b) (16+20+32):4=
c) (35+45+30):5=
DAU COROANA

Răspuns :

Denisa2051
a ) (3+2+5):7
10:7=-1,42857143
b) (4+5+8):4
17:4=4,25
c) (35+45+30):5
(7+9+6):5
22:5=4,4
[(21:7)+(14:7)+(35:7)]=(3+2+5)=10
[(16:4)+(20:4)+(32:4)]=(4+5+8)=17
[(35:5)+(45:5)+(30:5)]=(7+9+6)=22

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