Răspuns :
10,5t carbune = 10500kg
m C = 10500x80/100
mC =8400kg
20% din 8400KgC
8400x20/100= 1680kgC
a) C + 2H₂ → CH₄
2C + O₂→ 2CO
C + O₂ → CO₂
C + 2S →CS₂
C + H₂O → CO + H₂
4C + Fe₃O₄ →3 Fe + 4CO↑
C +2H₂SO₄ → CO₂ + 2SO₂ + 2H₂O
b) 12 1
C + 2H₂ → CH₄ MCH4 = 16
1680 x x= 1680x1/12
x = 140kmoli CH₄........140x16kgCH4= 2240kgCH4
10% din 8400KgC.................840kgC
2x12 2x28
2C + O₂→ 2CO
840 y y = 840x2x28/2x12 y =1960kgCO ........70kmoliCO
15% din 8400kg C........ 1260kgC
12 44
C + O₂ → CO₂
1260 z z = 1260x44/12 z =4620kgCO₂ ............105 kmoliCO₂
15% din 8400kgC.................1260kgC
12 76
C + 2S →CS₂
1260 t t= 1260x76/12 t = 7980kgCS2..................105 kmoliCS2
5% din 8400kgC .................420kgC
12 28 2
C + H₂O → CO + H₂
420 m n m =420x28/12 m=980kgCO........35kmoliCO
n = 420x2/12 n = 70kgH2.........35kmoliH2
10% din 8400kgC............840kgC
4x12 4x28
4C + Fe₃O₄ →3 Fe + 4CO↑
840 r r = 840x4x28/4x12 r=1960kg.CO....70kmoliCO
25% din 8400kg...............2100kg
12 44 2x64
C + 2H₂SO₄ → CO₂ + 2SO₂ + 2H₂O
2100 a b
a= 2100x44/12 a = 7700kgCO2...........175kmoliCO2
b = 2100x2x64/12 b =22400kgSO2.....350kmoliSO2
d)12 2x32
C + 2S → CS₂
1260 c c= 1260x2x32/12 c =6720kg S pur
100kg S..........................80kg S pur
d ...................................6720kg S pur
d = 100x6720/80
d =8400kg S cu impuritati
m C = 10500x80/100
mC =8400kg
20% din 8400KgC
8400x20/100= 1680kgC
a) C + 2H₂ → CH₄
2C + O₂→ 2CO
C + O₂ → CO₂
C + 2S →CS₂
C + H₂O → CO + H₂
4C + Fe₃O₄ →3 Fe + 4CO↑
C +2H₂SO₄ → CO₂ + 2SO₂ + 2H₂O
b) 12 1
C + 2H₂ → CH₄ MCH4 = 16
1680 x x= 1680x1/12
x = 140kmoli CH₄........140x16kgCH4= 2240kgCH4
10% din 8400KgC.................840kgC
2x12 2x28
2C + O₂→ 2CO
840 y y = 840x2x28/2x12 y =1960kgCO ........70kmoliCO
15% din 8400kg C........ 1260kgC
12 44
C + O₂ → CO₂
1260 z z = 1260x44/12 z =4620kgCO₂ ............105 kmoliCO₂
15% din 8400kgC.................1260kgC
12 76
C + 2S →CS₂
1260 t t= 1260x76/12 t = 7980kgCS2..................105 kmoliCS2
5% din 8400kgC .................420kgC
12 28 2
C + H₂O → CO + H₂
420 m n m =420x28/12 m=980kgCO........35kmoliCO
n = 420x2/12 n = 70kgH2.........35kmoliH2
10% din 8400kgC............840kgC
4x12 4x28
4C + Fe₃O₄ →3 Fe + 4CO↑
840 r r = 840x4x28/4x12 r=1960kg.CO....70kmoliCO
25% din 8400kg...............2100kg
12 44 2x64
C + 2H₂SO₄ → CO₂ + 2SO₂ + 2H₂O
2100 a b
a= 2100x44/12 a = 7700kgCO2...........175kmoliCO2
b = 2100x2x64/12 b =22400kgSO2.....350kmoliSO2
d)12 2x32
C + 2S → CS₂
1260 c c= 1260x2x32/12 c =6720kg S pur
100kg S..........................80kg S pur
d ...................................6720kg S pur
d = 100x6720/80
d =8400kg S cu impuritati