👤
Elly1117
a fost răspuns

lim x tinde la 2 x la 3 +x -10 / x la 3 - 3x -2

Răspuns :

C04f
[tex] \lim_{x\to 2} \frac{x^3+x-10}{ x^{3}-3x-2 }= \lim_{x \to 2} \frac{(x-2)( x^{2} +2x+5)}{(x-2)( x^{2} +2x+1)}= \lim_{x \to 2} \frac{ x^{2} +2x+5}{ x^{2} +2x+1}= \frac{13}{9} [/tex]

Alte intrebari