6. 1mol Zn...............65gZn
n .........................13g Zn
n= 13/65 MZnSO4 = 65 + 32+64
n= 0,2 moliZn = 161
65 161 2
Zn + H2SO4 → ZnSO4 + H₂↑ M H2 = 2
13 x y
x= 13x161/65 x = 32,2gZnSO4 n=m/M n= 32,2/161
n= 0,2moli ZnSO4
y = 13x2/65 y = 0,4gH2 nH2 =0,4/2 n = 0,2moliH2
3x56 4x2
7. 3Fe + 4H2O → Fe3O4 + 4H2
x 200
x = 168x200/8 x = 4200kgFe
n = m/M n= 4200/56 n = 75moli Fe
