Răspuns :
a =2^(n+5)+ 2^(n+1) +3x2^(n+2)=
=2^n×(2^5+ 2^1 +3x2^2)=
=2^n×(32+ 2 +12)=
=2^n×46 deci se divide cu 46
=2^n×(2^5+ 2^1 +3x2^2)=
=2^n×(32+ 2 +12)=
=2^n×46 deci se divide cu 46