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Nicolaemihaela
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Progresie geometrica b5=1/27 si b8=1/729
Sa se afle ratia si primul termen

Răspuns :

Lucasela
b5=b1xq^4=1/27,  (^ -simbol pentru putere)
b8=b1xq^7=1/729

b8/b5=1/729:1/27=1/27
(b1xq^7)/(b1xq^4)=1/27
=>q^3=(1/3)^3
=>q=1/3, ratia
b5=b1xq^4
1/27=b1x1/81 =>b1=1/27:1/81
b1=(1/27)x81/1=3
 b1=3 si  q=1/3

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