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Rezolvati in R inecuatia 2x-1 supra 3 mai mica decat 3x+2 supra 2. Ajutati.mama,va rog frumos.

Răspuns :

Veronica0
(2X-1)/3<(3X+2)/2
(2x-1)/3-(3x+2)/2<0
(4x-2-9x-6)<0
-5x-8<0
-5x<8
-5x<8
x>-8/5
x apartine (-infinit, -8/5).
Sper ca te-am ajutat!

0000000
[tex] \frac{2x-1}{3}< \frac{3x+2}{2}|*6 \\ 2(2x-1)<3(3x+2) \\ 4x-2<9x+6|+2 \\ 4x<9x+8|-4x \\ 5x+8>0|-8 \\ 5x>-8|:5 \\ x> - \frac{8}{5} \\ x \in (- \frac{8}{5}, \infty ) [/tex]

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