Răspuns :
Se duce prin punctul A o paralela la A'B' care intersecteaxa BB' in B"
AB" ⊥ BB' ⇒ ΔABB" dreptunghic in B" iar AB"= A'B' , BB" = BB'-AA' = 9 -6 =3
In Δ ABB" aplic TP AB"² = AB² - BB"²
AB"² = 5² - 3²
AB"² = 25 - 9
AB"² = 16
AB" = √16
AB" =4 ⇒ A'B' = 4
AB" ⊥ BB' ⇒ ΔABB" dreptunghic in B" iar AB"= A'B' , BB" = BB'-AA' = 9 -6 =3
In Δ ABB" aplic TP AB"² = AB² - BB"²
AB"² = 5² - 3²
AB"² = 25 - 9
AB"² = 16
AB" = √16
AB" =4 ⇒ A'B' = 4
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