Răspuns :
1.Calculez masa de acid din solutie
c=mdx100/ms
49= mdx100/900---> md=441g H2SO4
din ecuatie, calculez masa de carbon( M,H2SO4=98g/mol)
1mol 2mol
C + 2H2SO4---> CO2+2SO2 + 2H2O
12g..........98g
x...............441g........................calculeaza x !!!!
2.deduc moli si masa de acid din ecuatia, stiind n,C= 3mol
3C + 4HNO3 _-----> 3CO2 +4NO+2H2O
3mol.......4mol
m,HNO3= 4molx63g/mol= 252g (M,HNO3=63g/mol)
deduc masa de solutie de acid
c= mdx100/ms
63= 252x100/ms...........................calculeaza ms !!!!!
c=mdx100/ms
49= mdx100/900---> md=441g H2SO4
din ecuatie, calculez masa de carbon( M,H2SO4=98g/mol)
1mol 2mol
C + 2H2SO4---> CO2+2SO2 + 2H2O
12g..........98g
x...............441g........................calculeaza x !!!!
2.deduc moli si masa de acid din ecuatia, stiind n,C= 3mol
3C + 4HNO3 _-----> 3CO2 +4NO+2H2O
3mol.......4mol
m,HNO3= 4molx63g/mol= 252g (M,HNO3=63g/mol)
deduc masa de solutie de acid
c= mdx100/ms
63= 252x100/ms...........................calculeaza ms !!!!!