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a fost răspuns

Simplificati:
2x²+2x supra 4x+4
x²-1 supra (x+2)²
x²-15 supra x²+10x+25

Răspuns :

0000000
[tex]\frac{2x^2+2x}{4x+4}= \frac{2x(x+1)}{4(x+1)}= \frac{x}{2} \\ \frac{x^2-1}{(x+1)^2}= \frac{(x+1)(x-1)}{(x+1)^2}= \frac{x-1}{x+1} \\ \frac{x^2-25}{x^2+10x+25}= \frac{(x+5)(x-5)}{(x+5)^2}= \farc{x-5}{x+5} [/tex]

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