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Daca a= 1 intreg si 2 supra 3,iar b+c=11 supra 15,calculați a×b + ac.
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Răspuns :

a=1 intreg si 2/3=(1*3+2)/3=5/3
b+c=11/15

a*b+a*c=a*(b+c)

5/3*11/15
55/45 |:5( simplificam prin 5)
11/9=1 intreg 2/9
a=1int2/3=5/3
b+c=11/15
a*b+ac=a*(b+c)=5/3*11/15=11/9=1,22