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ce masa de acid propionic si alcool metilic se va consuma pentru a obtine 25,6 g ester?

Răspuns :

Puia68
M,acid= 74g/mol
M,alcool= 46g/mol
M,ester= 102g/mol

74g..........................46g.....................................102g
CH3-CH2-COOH+ CH3-CH2-OH---->CH3CH2COO-CH2-CH3+ H2O
x.................................y................................................25,6g  
x=m,acid= 25,6x74/102=..........................calculeaza !!!

y=m,alcool= 25,6x46/102=..........................calculeaza !!!