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a fost răspuns

Introduceti factorii de sub radical:2√5 ;5√3; 4√2; 8√3; 9√2; -7√3; -2√6; -10√5; 1,2√7; 2/3√5; 1/2√2; 1 intreg si 1/2√7; -0,5√10; -0,(3)√2; -2,5√10; -1,4√3; 12√7; 2√11; -5√13; -9√7.Va rog frumos!

Răspuns :

Renatemambouko
2√5=√20
5√3=√75
4√2=√32
8√3=√192
9√2=√162
-7√3=√147
-2√6=√24
-10√5=√500
1,2√7=√10,08
2/3√5=√20/9
1/2√2=√1/2
1 intreg si 1/2√7=3/2√7=√63/4
-0,5√10=√2,5
 -0,(3)√2=-1/3√2=√2/9
-2,5√10=√62,5
 -1,4√3=√5,88
12√7=√1008
 2√11=√44
 -5√13=√325
 -9√7=√567

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