%X=masa halogen/masa halogenura * 100=>masa halogen = %X * masa halogenura/100 => masa halogen = 71,43 * 224 / 100 = 160 g halogen masa molara halogen = 160 g/mol=>2x=160 (pt ca este halogen are 2 atomi in molecula)=>x=80 g/mol=> Bromul 224-160=64 g =>masa molara=64g/mol=> Cuprul Halogenura este clorura de brom!!!