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Leyla111
a fost răspuns

Gaseste numarul abc daca b=3a c=b×1+2

Răspuns :

Rutasepetys
c=3a+2=> abc= a×3a×3a+2 => a³× 3²+2 = a³× 12
abc=100a +10b+c
abc=100a+(3a)*10+b*1+2
abc=100a+30a+3a+2
abc=133a+2
Daca a=1
abc=135
b=3*1
c=3+2=5
abc=135

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