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Calculati: (x+2) la puterea 2 , (-x la puterea 3 +1 )la puterea 2 ,(-a - 2 ) la puterea 2 , (x-3) la puterea 2, (1-2x) la puterea 2, (a la puterea 2 - 3b ) la puterea 2 , ( 3x + 4y ) la puterea 2, (0.5 + 1 ) la puterea 2 ( -1,6x la puterea 2 + 0.1 ) , (radical/a - radical/b ) la puterea 2, (2radical3 + 1) la puterea 2 , (3x-radical/5) la puterea 2

Răspuns :

Eduardberdagaozhbcw
(x+2)^2=x^2+4x+4
[(-x)^(3+1)]^2=(-x)^(4x2)=-x^8
(-a-2)^2=a^2+4a+4
(x-3)^2=x^2-6x+9
(1-2x)^2= 1-4x+4x^2
[a^(2-3b)]^2= a^(4-12b+9b^2)
a^4/a^12b*a^9b^2
(3x+4y)^2=9x^2+24xy+16y^2
(✓a-✓b)^2= a+2ab+b
(2✓3+1)^2= 12+4✓3+1=13+4✓3
(3x-✓5)^2= 9x^2-6x✓5+5

la -1.6x la puterea 2+0.1 nu stiu sorry

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