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Fulger33
a fost răspuns

n=5la 78:1254ori257:5 la 32

Răspuns :

[tex]5^{78} : 1254 * 257: 5^{32} = \frac{5}{1254}^{78} * \frac{257}{5^{32}} = \frac{5}{1254}^{46} *257= \frac{257*5}{1254}^{46} [/tex]

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