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DutaRobertMihai
a fost răspuns

calculati:3x(2 la puterea 5+2 la puterea 4-2 la puterea3)+[25 la puterea 10-(5 la puterea 5)totul la 4]:(3 la puterea 100-2 la puterea 100)

Răspuns :

Didi12342
3×(2^5+2^4-2^3)+[25^10-(5^5)^4]:(3^100 - 2^100) =

= 3×2^3×(2^2+2^1- 1)+(5^20-5^20):(3^100-2^100) =

= 3×8 × (4+2-1) + 0:(3^100-2^100) =

= 24 × 5 + 0 =

= 120
3(2⁵+2⁴-2³)+[25¹⁰-(5⁵)⁴]:(3¹⁰⁰ - 2¹⁰⁰) =

= 3·2³·(2²+2-1)+(5²⁰-5²⁰):(3¹⁰⁰-2¹⁰⁰) 

= 3·8 × (4+2-1) + 0:(3¹⁰⁰-2¹⁰⁰)

= 24 × 5 + 0

= 120

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