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Rensnk2
a fost răspuns

Scrie numerele x=[2^30^2•(2^6)^100+(32^4)^100:2^500]•2 si y=5•(3^2002-3^2001-9^1000) ca patrate de numere naturale

Răspuns :

Assan123
X=(2^900×2^600+32^400÷2^500)×2
X=(2^1500+2^2000:2^500)×2
X=(2^1500+2^1500)×2
X=2^1500 (1+1)×2
X=2^1500×2×2
X=2^1502
X=(2^751)^2 este patrat
Y=5×3^2000 (3^2-3-1)
Y=5×3^2000×5
Y=5^2×(3^2)^1000
Y=(5×3^1000)^2 este patrat

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