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Andreea678
a fost răspuns

Efectueaza calculul:

a) 10+4*3 la puterea 2-7*5-(3 + 2 la puterea 3)
b) 2017-{[42-(5 la puterea 2*14-85*4)*2]*3+2 la puterea 6}
c) (10 la puterea 2-7 la puterea 2 + 5 la puterea 4)*(223 la puterea 0 + 1 la puterea 1500)

Dau coroana

Răspuns :

Carmenelenasta
a) 10+4×3^2-7×5-(3+2^3)=
10+4×9-7×5-(3+8)=
10+4×9-7×5-11=
10+36-35-11=46-35-11=11-11=0

b)2017-{[42-(5^2×14-85×4)×2]×3+2^6}=
2017-{[42-(25×14-85×4)×2]×3+64}=
2017-{[42-(350-340)×2]×3+64}=
2017-[(42-10×2)×3+64]=
2017-[(42-20 )×3+64]=
2017-(22×3+64)=
2017-(66+64)=2017-130=1 887

c)(10^2-7^2+5^4)×(223^0+1^1500)=
(100-49+625)×(1+1)=(51+625)×2=676×2=1352

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