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a fost răspuns

Descompune scoțand factor comun.

3x+3y

2√2a-4b=

x²+x³=


12-12y=

bx²+b²=

3√2x-3√6y=

x³-x²+x=

a³-2a²=

0,5p+q=

1 supra 2a-1 supra 4b=

a²-ab=

3x+6x²-x=

x²+x²-x=

ay²+az-ax=

a⁵x+a³+a³y+a⁶=

6a-6b-6c=

2x⁴-4x²+12x=

11x-22=

3√2a+√2b=

1 supra 5x+ 2 supra y-3 supra 5z=

Răspuns :

3x+3y= 3(x+y)
2√2a-4b=2(√2a-2b)
x²+x³=x²(1+x)
12-12y= 12(1-y)
bx²+b²=b(x²+b)
3√2x-3√6y=3√2(x-√3y)
x³-x²+x=x(x-x²+1)
a³-2a²=a²(a-2)
0.5p+p=p(0.5+1)
a²-ab=a(a-b)
3x+6x²-x=x(3+6x-1)
x²+x²-x=x(x+x-1)
ay²+az-ax=a(y²+z-x)
a^5x+a³+a³y+a^6=a³(a²x+1+y+a³)
6a-6b-6c=6(a-b-c)
2x^4-4X²+12x=2x(x³-2x+6)
11x-22=11(x-2)
3√2a+√2b=√2(3a+b)


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