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a fost răspuns

rezolvati in multimea numerlor naturale ecuatia: (3x-1)x(x+3)=(1-3x)(x+2)

Răspuns :

(3x-1)(x+3)=(1-3x)(x+2)
3x²+9x-x-3=x+2-3x²-6x
3x²+9x-x-3=x+2-3x²-6x
3x²+8x-3=-5x+2-3x²
3x²+8x-3+5x-2+3x²=0
6x²+13x-5=0
x=-13+-√13²-4*6*(-5)/2*6
x=-13+-√169+120/12
x=-13+-√289/12
x=-13+-17/12
x=-13+17/12
x=-13-17/12
x=1/3
x=-5/2
deci x₁=-5/2 si/sau x₂=1/3

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