Răspuns :
x²-3x+6=0
Δ=b²-4ac
Δ=(-3)²-4×1×6
Δ=9-24=-15
x₁=(-b+i√-Δ)/2a
x₂=(-b-i√-Δ)/2a
x₁=(3+i√15)/2
x₂=(3-i√15)/2
Δ=b²-4ac
Δ=(-3)²-4×1×6
Δ=9-24=-15
x₁=(-b+i√-Δ)/2a
x₂=(-b-i√-Δ)/2a
x₁=(3+i√15)/2
x₂=(3-i√15)/2