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2^{0}+2^{1}+2^{2}+2^{3}+2^{4}+2^{5}+2^{6}+...+2^{2003}=

Răspuns :

Didi12342
S = 2^0+2^1+2^2+2^3+2^4+..+2^2003 |×2

2×S = 2^1+2^2+2^3+2^4+2^5+...+2^2004

2×S-S = 2^2004 - 2^0

S = 2^2004 - 1

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