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Maxinfinite8
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Răspuns :

HawkEyed
[(2^3)^4: (2^2)^5 + (3^3)^9 : 3^24 + 2^12 : 2^11)] : 3 = 
[ 2^12 : 2^10  + 3^27 : 3^24 + 2] : 3 =
[ 2^2 + 3^3 + 2] : 3 =
[ 4 + 27 + 2] : 3 
33 : 3 = 
11 
Didi12342
(8^4 : 4^5 + 27^9 : 3^24 + 2^12 : 2^11) : 3 =

= [(2^3)^4:(2^2)^5+(3^3)^9:3^24+2^1] :3 =

= (2^12 : 2^10 + 3^27 : 3^24 + 2) : 3 =

= (2^2 + 3^3 + 2) : 3 =

= (4 + 27 + 2) : 3 =

= 33 : 3 =

= 11

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