Fie x=cel mai mic nr≠0
x:8=c1 rest 7
x:10=c2 rest 9
D=C•Î+R ; R<Î
x=8c1+7 => x=8c1+8-1 => x+1=8(c1+1) => (x+1) se divide cu 8
x=10c2+9 => x=10c2+10-1 => x+1=10(c2+1) => (x+1) se divide cu 10
=> x=c.m.m.m.c. al nr 8 si 10
8=2³
10=2•5
————
x=[8;10]=2³•5=8•5=40
Sper ca te.am ajutat!!!
