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Nicusor97
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1)√x-1+√x+3=8
2) √5-x=x+1
3√x²-x²+5=x

Răspuns :

Renatemambouko
1)√x-1+√x+3=8
2√x=6
4x=36
x=9

2) √5-x=x+1
2x=√5-1
x=(√5-1)/2

3.√x²-x²+5=x               
√x²=x
x-x²+5=x
x²=5
x=√5

√x²=-x
-x-x²+5=x
x²+2x-5=0
Δ=2²-4×(-5)=4+20=24
x₁=(-2+√24)/2=(-2+2√6)/2=-1+√6
x₂=(-2-√24)/2=(-2-2√6)/2=-1-√6

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