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Qwertyuiop1234567890
a fost răspuns

aratati ca logaritm in baza 3 din1/9 +radical de ordin trei din 27 =1

Răspuns :

Davidpiscot
[tex]log_3 \frac{1}{9}+ \sqrt[3]{27}=1\ \textless \ =\ \textgreater \ -2+3=1 \ \textless \ =\ \textgreater \ 1=1 (A) ~log_3 \frac{1}{9}=log_3 (\frac{1}{3}) ^2 [/tex]
[tex]2log_3 \frac{1}{3}=2*(-1) ~ ~ \sqrt[3]{27}= \sqrt[3]{3^3}=3^ \frac{3}{3} =3 [/tex]


[tex]\it log_3 \dfrac{1}{9} +\sqrt[3]{27} = log_31 - log_39+3 = 0-2+3=1[/tex]


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