2414:n= c1 rest 17=>c1*n+17=2414=>c1*n=2414-17=>c1*n=2397 si n≠1 (1)
1856:n= c2 rest 23=>c2*n+23=1856=>c2*n=1856-23=>c2*n=1833 si n≠1 (2)
Descompunem in factori primi:
2397=3 * 17 * 47
1833=3 * 13 * 47
Aflam divizorii comuni tuturor celor 2 numere:2397 si 1833
1; 3; 47; 141 (3)
Din (1),(2) si (3)=>n∈ {141}
