Răspuns :
(n+4; 3n+13)=1
Pp: (n+4; 3n+13)=d
d/n+4 (·3)=d/3n+12
d/3n+13(·1)=d/3n+13
d/(3n+13)-(3n+12)
d/3n+13-3n-12
d/13-12
d/1
d∈D₁ {1}
d=1
Pp: (n+4; 3n+13)=d
d/n+4 (·3)=d/3n+12
d/3n+13(·1)=d/3n+13
d/(3n+13)-(3n+12)
d/3n+13-3n-12
d/13-12
d/1
d∈D₁ {1}
d=1