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Totipttoti
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Calculati folosind regula a^m:a^n=a^m-n:
A)13^6:13/5
B)23^7:23^2:23
C)(2^3)^5:2^10
D)11^50:11^45-11^5
E)(3^2*5)^3:(3^6*5^3)
F)4^12:2^23+9^15:3^29
G)(3*3^2*3^3*3^200):9^103
Repedeeeee dau coroanaaaaaa

Răspuns :

2006angela
a)13^(6-5)=13
b)23^(7-2-1)=23^4
c)2^15:2^10=2^5
d)11^(50-45)-11^5=11^5-11^5=0
e)3^6*5^3:3^6*5^3=1
f)(2^2)^12:2^23 +(3^2)^15:3^29= 2^24:2^23+3^30:3^29= 2^1+3^1=5
g) 3^(1+2+3+200):(3^2)^103=3^206:3^206=1

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