Răspuns :
x+y+z=111
x=(y+z)/2
(y+z)/2+y+z=111
y+z=a
a/2+a=111 /*2
a+2a=222
3a=222
a=74
y+z=74
x=(y+z)/2
(y+z)/2+y+z=111
y+z=a
a/2+a=111 /*2
a+2a=222
3a=222
a=74
y+z=74
a+b+c=111 si a=(b+c) / 2
=> (b+c) / 2 + b+c = 111 | *2
( b+c) + 2(b+c) = 222
3*(b+c) = 222
(b+c) = 222:3=74
=> (b+c) / 2 + b+c = 111 | *2
( b+c) + 2(b+c) = 222
3*(b+c) = 222
(b+c) = 222:3=74